That's a big drop.

The problem is dissipating the heat from whichever device you choose to use to drop the voltage.

The first thing that you need to know is the current draw

(load in amps) of the device so you can choose the right bits to use.

As it's nominally a battery powered device it's likely to be low, in the region of milliamps.

It's many years since I have done any analogue electronics design, so I do not know if a chip is available to do exactly what you want.

I doubt it though.

If not then you are going to need a 5V voltage regulator plus potential divider to get you safely down to 1.5 Volts, and that is not something that I can easily describe here.

It's also not something that you can knock up in five minutes unless you know what you are doing.

Best to use a battery and switch matey! You could always use a relay driven from the ignition instead of a switch to connect the battery power if you wanted auto turn on

/ off.
